AUTOEVALUACIÓN

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1).

f(n)

1

− 1

()1 1

=− .

f()1 = =− =− 025 12 +344 2

()1 1

− 1

f()2 = == 014 22 +377 = .

3

()1 1

− 1 =− .

f()3 = =− =− 008

32 +3 12 12

4

()1 1

− 1 = .

f()4 = == 005

2

4 +3 19 19

5

()−11

=− .

f()5 = =−005 52 +3 28 6

()−11

f()6 = ==002

2. 6 +3 39

2). N = 50 b = 38 d = 35 – 38 = – 3 f ( 1 ) = b

fn b (n−1)d

() =+

f() =38 +(50 −1)( − )50 3

=38 +()( 3)49 −

=−109

3),

nf[21 +− d

() ( n 1)]

Sn=

() 2

31 2 126 + 31 −1 −9

[( )( )() ]

S()31 = 2

[ +−

31 252 ( 270)]

= =−279

2

1

4). n = 10 q =

a = 2 2

n−1

fn =q

() a

1 ⎤9 221

10 ⎣2  512 2256 16

f() =  2 == ==.0625

6 2n−1

18(−3)

n=1

f ()2

5). n = 1 q =

f ()1

0

 2⎞

f() = −⎟=18118 ⎜

⎝3⎠

 2⎞1

f() =18 ⎜

2 − ⎟=−12

⎝3⎠

n

f()[−q ]

11 sn() ==

1−q

6

⎡⎤

 2  64 ⎞

18 1 ⎢−−⎟18 1 −

⎜⎟

⎢⎝3⎠ ⎝729

⎣⎦

s() =

6 =  2 5

1−−⎜⎟

⎝3⎠3 1152

18 −729s() =6 /

53 1330 81

266 s() =6 =

5 27 3 266

ó .

s()6 =985

27

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